Statistics Problem Solving

A contestant who selects either of the two doors with a goat behind it and then switches will always get the car.

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Switching raised that probability to two in three that you'll select a car.

Said another way: A player whose strategy is to always switch will only lose when the door they initially selected has a car behind it.

That means that the probability that two people in the office share a birthday is 1 -- 0.4927 = 0.5073, or 50.7%.

A gambler has a certain amount of money ("B") and is playing a game of chance with some win probability less than 1.

We've selected five classic problems solved in unconventional ways that can help one get a new way to understand the way that data can be misleading and the story on the surface can take people in the wrong direction.(1) THE MONTY HALL PROBLEMSay you're on a game show where there are three doors. Then, you have the option of either staying with your door or switching to the last unopened door. ANSWER: SWITCH This is actually based on a real game show, and the result has been the source of controversy for years.